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NeX [460]
3 years ago
7

Can someone please help me with this problem?

Mathematics
1 answer:
pentagon [3]3 years ago
7 0
The slope would be 0 because if you put in the coordinates with the formula, you would get the slope as 0. This also makes sense because both points have the same y point, so that means that the line wasn’t travelling up or down. And since it was only going through -8 that would be the y-intercept.

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Can anyone help thank you ggg
polet [3.4K]
I believe it is 1. Function 2. Not a function 3. Function 4. Not a function. I hope this helps! :)
5 0
3 years ago
Read 2 more answers
Find the value of X.
hram777 [196]

Answer:

X=6 I believe

Step-by-step explanation:

3 0
3 years ago
I NEED HELP PLEASE !
MrRa [10]

Answer:

x = 4, -2 1/2

Step-by-step explanation:

factors:

(2x + 5) (x - 4)

set each factor equal to zero:

2x + 5 = 0

2x = -5

x = -5/2

x - 4 = 0

x = 4

6 0
3 years ago
Justin has three goldfish and one turtle. Write a fraction to represent the part of his pets that are goldfish.
Troyanec [42]

Answer:

3/4

Step-by-step explanation:

3 goldfish

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7 0
3 years ago
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What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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