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3 years ago

(x-4)2 + (y + 3)2 =

Mathematics

1 answer:

White raven [17]3 years ago

7 0

Answer:

the answer is 2x+2y-2

then all you need to do is write in standard form.

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A line goes through the points (-1,9) and (1,1).Write the equation of this line in point slope form using one of these points.

Mashcka [7]

Answer:

y-9= -4(x+1)

Step-by-step explanation:

First, you should know what the format for point slope form is. y-y1=m(x-x1). Now, fill in the points to the x1 and y1 variables. It doesn't matter what ordered pair you use. If the number you fill in is negative, for example, -1, change it to a positive 1. If you're plugging in a positive number such as 9, it becomes -9. Now, it may look like this: y-9=m(x+1). However, you still need to find slope. You can use the expression y-y1/x-x1. 9-1=8. -1-1= -2. So, your slope is 8/-2. However, you can simplify this to -4. Now, plug in -4 to your equation to have your final answer: y-9=-4(x+1).

3 0

3 years ago

PLEASE I JUS NEED HELP PLEASE

nika2105 [10]

Answer:

I am sorry

Step-by-step explanation:

4 0

2 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$