How do i divide decimals by whole numbers

The function a(1) =1/2I^2 describes the area of an isosceles right triangle with leg I. Make a table of values for I=1,2,3 and 4

prohojiy [21]

Functions can be represented using equations, graphs and tables.

The function is given as:

$a(l) = \frac 12 l^2$

When l = 1, we have:

$a(1) = \frac 12 \times 1^2$

$a(1) = 0.5$

When l = 2, we have:

$a(2) = \frac 12 \times 2^2$

$a(2) = 2.0$

When l = 3, we have:

$a(3) = \frac 12 \times 3^2$

$a(3) = 4.5$

When l = 4, we have:

$a(4) = \frac 12 \times 4^2$

$a(4) = 8.0$

Represent the above results as a table, we have:

1 0.5

2 2.0

3 4.5

4 8.0

Read more about tables and functions at:

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8 0

3 years ago

According to a certain country's department of education, 39.9% of 3-year-olds are enrolled in day care. what is the probabi

Yuliya22 [10]

The probability would be 39.9%

The given probability states that 39.9% of the 3 years olds are in daycare. Therefore, it would be obvious to assume that if you randomly selected a 3 year old, that would be the probability that he/she is in daycare.

8 0

3 years ago

You have 24 months left until you graduate and you plan on buying yourself a new $20,000 car on graduation day. If you invest $3

shusha [124]

Answer: No, the money won't be enough to buy the car

Step-by-step explanation:

you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.

The principal amount, p = 300

He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So

n = 4

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

It was compounded for a total of 24 months. This is equivalent to 2 years. So

n = 2

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount that would be compounded at the end of n years.

A = 300(1 + (0.04/4)/4)^4×2

A = 300(1 + 0.01)^8

A = 300(1.01)^8

A = $324.857

The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car

3 0

4 years ago

Look at the system of equations below.

Annette [7]

Answer:

Substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen. Therefore, elimination is the suitable method for solving this system.

Step-by-step explanation:

Let us consider the system of equation below.

$4x-5y=3$

$3x+5y=13$

Elimination method sounds the most appropriate option to solve the given system of equations as we can easily sort out an equation in one variable x in minimal steps by just adding the both equations as the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation, and we can determine an equation in one variable x.

Adding both equations will eliminate the y-variable and we can easily sort out the value of x from the resulting equation.

As the given system of equation

$4x-5y=3$ $......[1]$

$3x+5y=13$ $......[2]$

Adding Equation 1 and Equation 2

$4x-5y+3x+5y=3+13$

$7x=16$

$x=$ $\frac{16}{7}$

Putting $x=$ $\frac{16}{7}$ in Equation [1]

$4x-5y=3$ $......[1]$

$y=$ $\frac{43}{35}$

Although substitution or graphing methods can also be used to bring the solution of the given system of equations, but using substitution or graphing method can be sometimes cumbersome or time-consuming as it would have to take some additional steps to solve the system.

For example, if we would have to use the substitution methods to solve the given system of equations, first we would have to solve one of the equations by choosing one of the equation for one of the chosen variables and then putting this back into the other equation, and solve for the other, and then back-solving for the first variable.

As the given system of equation

$4x-5y=3$ $......[1]$

$3x+5y=13$ $......[2]$

Solving the equation 2 for x variable

$3x=13-5y$

$x=\frac{13-5y}{3}$

Plugging $x=\frac{13-5y}{3}$ in equation [1]

$4(\frac{13-5y}{3}) -5y=3$

$y = \frac{43}{35}$

Putting $y = \frac{43}{35}$ in Equation 2

$3x+5y=13$ $......[2]$

$x = \frac{16}{7}$

So, you can figure out, we have to make additional steps when we use substitution method to solve this system of equations.

Similarly, using graphing method, it would take a certain time before we identify the solution of the system.

Hence, from all the discussion and analysis we did, we can safely say that substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen.

Therefore, we agree with the student argument that Elimination is the best method for solving this system because the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation.

Keywords: substitution method, system of equations, elimination method

Lear more about elimination method of solving the system of equation from brainly.com/question/12938655

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4 0

4 years ago

PLEASE HELPP!

r-ruslan [8.4K]

Answer:

$1.25

September

$30

Step-by-step explanation:

Let's take this a step a time.

First we need to find how much the price of the flowers were in September.

We know that each flower cost $1.50 on October.

The October price was a 20% increase of the September price.

To calculate for the price of the flowers on September, we can solve it like this:

Let x = Price during September

1.2x = 1.50

We used 1.2 because the price of $1.50 is 120% of the original price.

Now we divide both sides by 1.2 to find x.

$\dfrac{1.2x}{1.2}=\dfrac{1.5}{1.2}$

x = 1.25

The price of the flowers during September was $1.25 each.

Now the 7th grade class earned 40% of the selling price of each flower.

40% = 0.40

To find how much they made on each month, we simply multiply the percentage to the price and the number of flowers sold.

September = 0.40 x 1.25 x 900

September = 0.5 x 900

September = $450

Now for October.

October = 0.40 x 1.50 x 700

October = 0.6 x 700

October = $420

The 7th Graders earned more on September.

They earned $30 more on September than October.

5 0

3 years ago