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2 years ago

Select the correct answer. -Plato- The Tangent line problem: Mastery test

Mathematics

1 answer:

melisa1 [442]2 years ago

3 0

Answer: 5x or 10x-3

Step-by-step explanation:

I got it wrong twice so these are the answers left. (plato)

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Where does the graph of y= sin x from x = 0 to x = 217 start?

choli [55]

Answer:

B) at an x-intercept

Step-by-step explanation:

Hope this helps :))

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2 years ago

16x²-102X=-36<br> How to write this in Vertex form

boyakko [2]

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Step-by-step explanation:

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2 years ago

3. Determine if the following triangle is a right triangle or not using the Pythagorean Theorem Converse. Triangle with side len

stepladder [879]

Answer:

false

Step-by-step explanation:

these measure do not form a right triangle

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1 year ago

Write an algebraic expression for the given quantity. Let x represent the unknown value.

Lelechka [254]

Answer:

Step-by-step explanation:

There is no equal sign.

1/2 x - 5*x

is all there is.

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2 years ago

(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim

aleksklad [387]

(i) Given that

$V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr$

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

$V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}$

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

$\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

Compute the integral:

$V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

$V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr$

$V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R$

$V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)$

$V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}$

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0

2 years ago