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vladimir2022 [97]
3 years ago
13

Solve this problem using the substitution method 2y-1/2y=2

Mathematics
1 answer:
stealth61 [152]3 years ago
6 0

Answer:

y=3/2and x =2

Step-by-step explanation:

You might be interested in
Literally answer any of the questions above and it’ll be the biggest help
Tcecarenko [31]

The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.

We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.

a) The cosine values repeat every 2π, so the general form of the smallest angle will be

... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ

b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is

... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ

c) Using these expressions with k=0, 1, 2, we get

... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}

3 0
3 years ago
Which is the correct calculation of the y-coordinate of point A? 0 (0 - 0)2 + (1 - y2 = 2 O (0 - 1)² + (0- y2 = 22 (0-0)² + (1 -
dimaraw [331]

Answer:

The y-coordinate of point A is \sqrt{3}.  

Step-by-step explanation:

The equation of the circle is represented by the following expression:

(x-h)^{2}+(y-k)^{2} = r^{2} (1)

Where:

x - Independent variable.

y - Dependent variable.

h, k - Coordinates of the center of the circle.

r - Radius of the circle.

If we know that h = 0, k = 0 and r = 2, then the equation of the circle is:

x^{2} + y^{2} = 4 (1b)

Then, we clear y within (1b):

y^{2} = 4 - x^{2}

y = \pm \sqrt{4-x^{2}} (2)

If we know that x = 1, then the y-coordinate of point A is:

y = \sqrt{4-1^{2}}

y = \sqrt{3}

The y-coordinate of point A is \sqrt{3}.  

4 0
3 years ago
Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500
Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 500, \pi = \frac{421}{500} = 0.842

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0
3 years ago
How much water would a 8 ft by 25 ft rectangle hold
ziro4ka [17]

what is the height? in order to calculate the amount of water a rectangular prism can hold, you must know the volume of that rectangular prism, therefore needing three unit factors, including the length, width, and height.... you gave me two factors, the length and the width, so i cannot help you

8 0
3 years ago
Find the sixth term of the sequence 1/2, -3/8, 9/32
sukhopar [10]

Answer:

The sixth term is -243/2048 ⇒ answer B

Step-by-step explanation:

* Lets explain the geometric sequence

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5  ,  10  ,  20  ,  40  ,  80  ,  ………………………. (×2)

# 5000  ,  1000  ,  200  ,  40  ,  …………………………(÷5)  

* General term (nth term) of a Geometric sequence:

# U1 = a  ,  U2  = ar  ,  U3  = ar²  ,  U4 = ar³  ,  U5 = ar^4

# Un = ar^(n-1), where a is the first term , r is the constant ratio

  between each two consecutive terms  and n is the position of the

  number in the sequence

- Ex: U5 = ar^4  ,  U7 = ar^6  ,  U10 = ar^9  ,  U12 = ar^11

- Lets solve the problem

∵ The sequence is 1/2 , -3/8 , 9/32

- Lets find the constant ratio r

∵ The first term is a = 1/2

∵ The second term is U2 = ar

∵ The second term  U2 = -3/8

∴ ar = -3/8

∴ 1/2 r = -3/8 ⇒ multiply both sides by 2

∴ r = -3/4

- Lets find the sixth term

∵ a = 1/2 and r = -3/4

∵ n = 6

∴ U6 = ar^5

∴ U6 = 1/2 (-3/4)^5 = 1/2 × -243/1024 = -243/2048

* The sixth term is -243/2048

8 0
3 years ago
Read 2 more answers
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