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3 years ago

What is the cube root of b^27

Mathematics

2 answers:

koban [17]3 years ago

4 0

9 the answer is 9 to find cube root just divide by 3

Mkey [24]3 years ago

4 0

Answer: b^9

Step-by-step explanation:

You divide 27 by 3. And get b^9

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photoshop1234 [79]

Answer:

it is similar- this ~ squiggly thing means similar

Step-by-step explanation:

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2 years ago

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vova2212 [387]

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Step-by-step explanation:

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3 years ago

10. A In the adjoining Figure, ab is perpendicular to bc and ed is to cd while bc=cd . prove i) triangle abc is corresponding to

xxTIMURxx [149]

Part (i)

1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)

2) Angles ABC and CDE are right angles (perpendicular lines form right angles)

3) Angles ABC and CDE are equal (all right angles are equal)

4) Angles ACB and DCE are equal (vertical angles are equal)

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Part (ii)

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2 years ago

Please help asap 25 points

Dafna11 [192]

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3 years ago

For f left parenthesis x right parenthesis equals StartRoot x EndRoot and g left parenthesis x right parenthesis equals 4 x plus

lara31 [8.8K]

Answer:

Step-by-step explanation:

Given that there are two functions f and g as

$f(x) = \sqrt{x} \\g(x) =4x+9$

We have to find the composition of functions.

Composition functions are calculated as the first function inside bracket and then the outside function of answer inside.

a) $fog= f{g(x)} =f(4x+9) = \sqrt{4x+9}$

b) $gof = g{f(x)} = g(\sqrt{x} )=4\sqrt{x} +9$

c) $fof = f(\sqrt{x} ) = \sqrt[4]{x}$

d) $gog = g(4x+9) = 4(4x+9)+9\\= 16x+45$

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3 years ago