Diagonally
the top of the closet
The polynomial x3+8 is equal to (x+2)(x2-2x+4)
Answer:
3
Step-by-step explanation:
3
+
11
⋅
(
8
−
4
)
÷
(
5
+
6
)
−
4
Subtract 4 from 8
.
3
+
11
⋅
4
÷
(
5
+
6
)
−
4
Multiply 11 by 4
.
3
+
44
÷
(
5
+
6
)
−
4
Find the common denominator.
Add 5 and 6
.
3
+
44
÷
11
−
4
Write 3 as a fraction with denominator 1
.
3/
1
+
44
÷
11
−
4
Multiply 3/
1 by 11/
11
.
3/
1
⋅
11
/11
+
44
÷
11
−
4
Multiply 3/
1 and 11
/11
.
3
⋅
11
/11
+
44
÷
11
−
4
Write −
4 as a fraction with denominator 1
.
3
⋅
11
/11
+
44
÷
11
+ −
4
/1
Multiply −
4
/1 by 11
/11
.
3
⋅
11
/11
+
44
÷
11
+
−
4
/1 ⋅
11
/11
Multiply
−
4
/1 and 11
/11
.
3
⋅
11
/11
+
44
÷
11
+ −
4
⋅
11
/11
Combine the numerators over the common denominator.
3
⋅
11
+
44
−
4
⋅
11
/11
Simplify each term.
Multiply 3 by 11
.
33
+
44
−
44
⋅
11/
11
Multiply −
4 by 11
.
33
+
44
−
44
/11
Simplify the expression.
Add 33 and 44
.
77
−
44/
11
Subtract 44 from 77
.
33
/11
Divide 33 by 11
.
3
Y-2=-3/2(x-2)
first of all, the slope of the line is -3/2, and there's only one equation that has that as a choice for the slope. Then you can take the x and y coordinates given in that equation you want to check and see if the line goes through that point. from the equation, (point-slope form y-y=m(x-x)) I know that the line should pass through point (2, -2), and looking at the graph, that is correct.
Answer:
Step-by-step explanation:
Since there exists a scalar
λ
λ
(namely
λ=a⋅b
λ=a⋅b
) such that
b=λa
b=λa
, the directions of the two vertices are the same (they are collinear). This implies that
|a⋅b|=|a||b|
|a⋅b|=|a||b|
.
So,
|a|=|(a⋅b)b|=|a||b||b|
|a|=|(a⋅b)b|=|a||b||b|
which implies that
|b|=1
|b|=1
