The given measurement of the Instagram photo is "4" by "4". And a poster enlargement is being printed with a scale factor of 8.5 .
So on using the scale factor of 8.5 , lengths of new sides are "8.5 *4" by "8.5 *4"
= " 34" by "34" .
So the new lengths of the enlarged pictures are of dimension "34" by "34" .
The answer is c because I took a great guess im putting the answer because I know no-one else would put the answer for this person when they need the answer but I need the answer so I took a great guess
Triangle ABC has vertices at A(3, 8) , B(11, 8) , and C(9, 12) . Triangle FGH has vertices at F(1, 3) , G(9, 3) , and H(7, 7) .
Alex17521 [72]
Hmm, (x,y)
x is horizontal or left right
y is vertical or up down
so
we see that A to F is move left 2 and down 5
B to G is left 2 and down 5
C to H is left 2 and down 5
so translatete ABC left 2 and down 5 and
translate FGH right 2 and up 5
not 1st option
2nd works
3rd works
4th is false
2nd and 3rd
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 152.5
For the alternative hypothesis,
µ ≠ 152.5
This is a two tailed test.
Since no population standard deviation is given, the distribution is a student's t.
Since n = 231
Degrees of freedom, df = n - 1 = 231 - 1 = 230
t = (x - µ)/(s/√n)
Where
x = sample mean = 148.9
µ = population mean = 152.5
s = samples standard deviation = 27.4
t = (148.9 - 152.5)/(27.4/√231) = - 2
We would determine the p value using the t test calculator. It becomes
p = 0.047
Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals
Answer:
what's the problem to your question?
