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Ipatiy [6.2K]
3 years ago
9

How many six-digit odd numbers are possible if the left digit cannot be zero?

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0
We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>
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Aisha wants to paint the four walls of her living room. Each wall is 2.6 m high and 3.5 m long. One wall has a door of 2.2 m by
Snowcat [4.5K]

Answer:

£22

Step-by-step explanation:

Area to be painted

4walls - door

a = 4(2.6 * 3.5) - 2.2 * 0.8

a = 34.64 m²

Paint needed

p = 34.64 / 8

p = 4.33

Must round up

p = 5 liters

Tins needed

t = 5/2

t = 2.5

must round up

t = 3

Cost

since 1 is free with 2 will pay for 2

c = 11 * 2

c = 22

£22

8 0
3 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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