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3 years ago

Which expressions are polynomials?

Mathematics

2 answers:

kenny6666 [7]3 years ago

6 0

Answer:

2x^4 − y

6 + w

z + 1

Step-by-step explanation:

exis [7]3 years ago

5 0

Answer:

It is 6+w, z=1, and 2x^4-y

Step-by-step explanation:

You might be interested in

Solve the equation 6+1/5q=10

Marat540 [252]

Answer:

q = 20

Step-by-step explanation:

1/5q = 4

q = 20

4 0

4 years ago

Safiya deposited money into a bank account that earned 6.5% simple interest each year. After 312 years, she had earned $36.40 in

Svetllana [295]

Answer: If the time is 3 1/2 years (most reasonable assumption)

Her initial deposit was $160

Step-by-step explanation: The basic formula for simple interest is

<em>i = prt i </em>is interest, P is principal (deposit) r is the percentage (converted to a decimal) and t is time, the number of years.

For this question, you have to rearrange the equation to solve for p.

So divide both sides by rt and you have

p = i/rt

Substitute the values given

p = 36.40/(0.065)(3.5)

8 0

4 years ago

A leaky pool loses 2 1/4 inches of water each day. Jermaine and Mildred are asked to determine the change in the amount of water

Studentka2010 [4]

Answer:

11 1/4 inches.

Step-by-step explanation:

2 1/4 times 5 = 11 1/4

3 0

3 years ago

Read 2 more answers

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

Which of the following is equivalent to the complex number i24?

Alika [10]

Answer: 1

Step-by-step explanation:

Rewrite as (i^4)^6

Rewrite i^4 as 1

Rewrite i^4 as (i^2) ^2

((i^2)) ^2)6

Rewrite i^2 as -1

((-1) ^2) 6

Raise -1 to the power of 2

1^6

One to any power is 1.

5 0

3 years ago