Answer:
Phillipa rode the most in May and rode the least in March.
Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March
Step-by-step explanation:
Given:
In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.
To find: the month when she rode the most and the month when she rode the least
Solution:
Distance travelled by Phillipa on her cycle in April = 13 . 5 + 8 . 7 + 11 . 1 = 65 + 56 + 11 = 132 miles
Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 = miles
Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles
So, she rode the most in May and rode the least in March
Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March
