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3 years ago

The mean age of 3 women in an office is 30 years old.

Mathematics

1 answer:

Hoochie [10]3 years ago

4 0

Answer:

32 years

Step-by-step explanation:

Here, we simply calculate the age of all first

For all men, we have 7(33) = 231

For all women = 3(30) = 90

So we simply have;

(90 + 231)/10 = 32.1

Approximately 32 years

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Help plz:))) I’ll mark u brainliest

egoroff_w [7]

Answer:

Im pretty sure it is c

Step-by-step explanation:

it gives us 2 angles add up to 180, but they are right next to each other. So we cant determine parallel lines.

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6 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

MODELING WITH MATHEMATICS A farmer plants a garden that contains corn and pumpkins. The total area (in square

laiz [17]

Answer:

The equation in standard form that models area of pumpkins is:

$A_p = A_G - A_c$

and the area is: $x^2+8x+2$

Step-by-step explanation:

Given that the garden has corn and pumpkins

The expressions are:

Total area of garden: $A_G = 2x^2+5x+4$

Area of Corn: $A_c = x^2-3x+2$

Area of Pumpkins: $A_p = ?$

The sum of areas of corn and pumpkins is the total area of the garden.

It can be expressed mathematically as:

$A_G = A_c+A_p$

If we have to find the area of pumpkins,

$A_p = A_G - A_c$

Putting the values

$A_p = (2x^2+5x+4) - (x^2-3x+2)\\A_p = 2x^2+5x+4-x^2+3x-2\\A_p = 2x^2-x^2+5x+3x+4-2\\A_p = x^2+8x+2$

The equation in standard form that models area of pumpkins is:

$A_p = A_G - A_c$

and the area is: $x^2+8x+2$

3 0

3 years ago

Someone explain how this is answer C? Big points!

Snowcat [4.5K]

Answer:

C. x = 15 * sin 18°

Step-by-step explanation:

sin A = Opposite / Hypotenuse

sin 18° = x / 15

x = 15 * sin 18°

4 0

3 years ago

Can someone help me please!!

Lynna [10]

Answer:

b because the value are correct

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers