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3 years ago

Which is the simplified form of r^-7+s^-12

Mathematics

1 answer:

grigory [225]3 years ago

5 0

Answer:

The simplest form is 1/r^7 + 1/s^12

Step-by-step explanation:

The given expression is r^-7+s^-12.

Notice that the exponents of both the base are negative

So, we will apply the rule which is:

a^-b = 1/a^b

Which means that to change the exponent into positive we will write it as a fraction:

r^-7+s^-12.

= 1/r^7 + 1/s^12..

Therefore the simplest form is 1/r^7 + 1/s^12....

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Type the correct answer in the box. Spell the word correctly.

Wittaler [7]

Answer:

Scarce demand / inflation

The word "scarce" means low on supplies or anything else.

Inflation is the term used when a price increases in the market.

These two terms together would best describe the higher demand.

Hope this helps, have a great day! ♥

7 0

2 years ago

At what point do the lines y = 6x – 18 and y=8x – 32 intersect?

anzhelika [568]

Answer:

(7, 24)

Step-by-step explanation:

Solve the system:

6x - 18 = 8x - 32

2x = 14

x = 7

y = 6(7) - 18

y = 24

4 0

2 years ago

On a coordinate plane, triangle A B C has points (negative 3, negative 1), (negative 2, negative 3), (1, negative 1) and is refl

andreev551 [17]

Answer:

A' = (-3, 3)

Step-by-step explanation:

If the points are as follows:

A = (-3, -1)

B = (-2, -3)

C = (1, -1)

When reflecting across a y axis the x values remain the same.

When reflecting across y = 1 the y values will remain equal distant from y = 1.

A' = (-3, 3) y value = |-1 - 1| = 2 + 1 = 3

B' = (-2, 5) y value = |-3 - 1| = 4 + 1 = 5

C' = (1, 3) y value = |-1 - 1| = 2 + 1 = 3

7 0

2 years ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the future value FV.

In order to see the rule of formation, let's see the value (in $) for the first few years

End of year 0

1,000

End of year 1(capital + interest + new deposit)

1,000*(1.09)+10

End of year 2 (capital + interest + new deposit)

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

End of year 3 (capital + interest + new deposit)

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the sum of a geometric sequence with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The present value PV is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

3 years ago

Help ASAP!!!!!!!!!!!!!!!

Airida [17]

1 hundredth+3 tenths= 3 hundredths

6 0

2 years ago