Why did the kindergartner take her books to the zoo?

Question 1 (5 points)<br>What sign makes the problem true?<br>-15 -16<br>a <<br>b ><br>c =

Debora [2.8K]

B i cant really tell how because thats hard for me to do but it is b

8 0

3 years ago

12 is 90% of what number?<br><br><br> with steps

a_sh-v [17]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here 12 is 90% of a number.
So we can say that 90% of That number is 12 .
In this way we can get the the number

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Let,

the number=x

<h3>According to the question ,</h3>

${:}\longrightarrow$ $\sf 90\% \:of \;x=12$

We know 90%=90/100
so add it

${:}\longrightarrow$ $\sf {\dfrac {90}{100}}\times x=12$

${:}\longrightarrow$ $\sf {\dfrac {90x}{100}}=12$

Now use cross multiplication method

${:}\longrightarrow$ $\sf 90x=12\times 100$

${:}\longrightarrow$ $\sf 90x=1200$

Now interchange sides .

${:}\longrightarrow$ $\sf x={\dfrac {1200}{90}}$

${:}\longrightarrow$ $\sf x={\dfrac {200}{15}}$

Answer will come in decimals so we take approximate value.

${:}\longrightarrow$ $\sf x=13.3$

${:}\longrightarrow$ $\sf x=approximately \:13$

$\therefore$ The number is 13.

6 0

2 years ago

A typical middle-income household in 1980 earned $34,757. A similar household in 2009 earned $38,550. What was the relative incr

S_A_V [24]

Given conditions are :

In 1980's, a typical middle-income household earned= $34,757

In 2009, a similar middle-income household earned= $38,550

And we have to find relative increase in income for these households from 1980 to 2009.

So first we will find the total increase in amounts.

$38550-34757=3793$

Relative increase = $\frac{3793}{34757}*100$

= 10.91% or rounding it off we get approx 11%.

Hence, the answer is 11%.

5 0

3 years ago

Read 2 more answers

What is the first quartile of the data displayed in this box-and-whisker plot?

ValentinkaMS [17]

4. 42,

Since Q1 is the first part of the box plot, and on the graph states
42

7 0

3 years ago

Read 2 more answers

a city has a population of 340,000 people suppose each year the population grows by 7% what will rhe population be after 12 year

NemiM [27]

So this is going to be an exponential equation, which the format is $y=ab^x$ , in which a is the initial value and b is the growth/decay rate.

In this case, a is going to be 340,000 and b is going to be 107%, or 1.07, since the population is going to be increasing by 7% and the equation is now $y=340000(1.07)^x$ .

Now replace x with 12 and solve.

$y=340000(1.07)^{12}$

Solve $1.07^{12}$ , and then if you don't round that answer and multiply it with 340000 you get $y=765745$ .

6 0

3 years ago