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3 years ago

Plz answer this i will mark u brianiest

Mathematics

1 answer:

Degger [83]3 years ago

7 0

Answer:

56 is 80% of 70

Step-by-step explanation:

Number line on top, two ticks are 35 & 56.

Number line on bottom, two ticks are 50% & 80%.

So, 56 is 80% of 70

Hope this helps!

Plz give brainliest if possible!

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Solve the equation. 33 = p – 6.71 A. –39.71 B. –26.29 C. 39.71 D. 26.29

jeka57 [31]

Answer

C. 39.71

Explanation

33 = p - 6.71

The first step is to make the like terms to be on the same side.

Add 6.71 on both sides of the eqution

33 + 6.71 = p - 6.71 + 6.71

39.71 = p

∴ p = 39.71

4 0

3 years ago

Y=2/5x+2 how do you graph it on a graph

ANTONII [103]

That is how you graph y=2/5x+2 since 2/5 is the slope and 2 is the y intercept.

8 0

3 years ago

68 increased by 75%

mash [69]

Let's see -

Follow the directions below to get your answer -

0.75 × 68 = 51

51 + 68 = 119

So, 119 is your answer

68 increased by 75% is 119.

↑ ↑ ↑ Hope this helps! :D

3 0

3 years ago

Read 2 more answers

Select the decimal that is equivalent to 1/8

iogann1982 [59]

The answer is 0.125....................................

5 0

3 years ago

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A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti

jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

$\pi = \frac{0.438 + 0.642}{2} = 0.54$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}$