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2 years ago

9

malamud and mohammed bought the same eight CD's but mohammed bought used CD's so each was half the price malamud paid. if the me

an price malamud paid in $16 and the median is $16.50 , what are the mean and median prices for mohammed's CD's?

1 answer:

Vlada [557]2 years ago

8 0

Answer: $8 , $8.25

Step-by-step explanation: It says “ half the price ” so half of 16 is ( 8 ) and half of 16.50 is ( 8.25 )

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The midpoint of (2,7) and (6,3)

White raven [17]

Answer:

3

Step-by-step explanation:

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2 years ago

If the angle NME = x+97, the angle EML = x+66, and the angle NML = 141, find the angle EML

defon

Answer:

∠ EML = 94°

Step-by-step explanation:

See the attached diagram.

The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.

Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°

Hence, (x + 97) + ( x + 66) + 141 = 360

⇒ 2x + 304 = 360

⇒ 2x = 56

⇒ x = 28

So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)

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3 years ago

A ramp has a slope of 1, what is the relationship between the rise and ?

adelina 88 [10]

Answer:

the rise over run. if a ramp has a slope of 1 the rise over one is most likely 1/1

Step-by-step explanation:

7 0

3 years ago

Find the value of x in the triangle listed here. If you could show me the steps, I would appreciate it.

-Dominant- [34]

Answer:

71°

Step-by-step explanation:

The triangle shown is an isosceles triangle. Isosceles triangles have two equal sides and two equal angles. When all 3 angles are added, it should have a sum of 180°. The tip of the triangle is the part of the triangle with the smallest degree/angle. So the two remaining angles are the same amount.

180°=38°+x+?

180°=38°+71°+71°

Both missing angles are the same degree, and when both are added to 38, it has a sum of 180. x is equal to 71°.

7 0

2 years ago

Read 2 more answers

Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by $\sqrt{x}$

$b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x} }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\$

Now, find a +b

$a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}$

Combine like terms

$= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}$

Now find (a + b)²

(a +b)² = $(\frac{2\sqrt{x} }{x})^{2}$

$= \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}$

Hint: $\sqrt{x} *\sqrt{x} =\sqrt{x*x}=x$

5 0

3 years ago