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3 years ago

Need help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Bingel [31]3 years ago

7 0

Step-by-step explanation:

Initial Value Increase Increase Final Value = 24 = 8% ↓ = 100 8 × 24 = 0.08 × 24 = 1.92 ↓ = 24 + 1.92 = 25.92

Ugo [173]3 years ago

4 0

Answer:

25.92

I hope this helps! ^^

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Please answer in a step by step explanation

Marizza181 [45]

Answer:

Step-by-step explanation:

its a

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3 years ago

Polygon ABCD is dilated by a scale factor of 2 with the center of dilation at the origin to create A'B'C'D'. If the endpoints of

Sonja [21]

The distance formula is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Take point A(0, -7) as (x₁, x₂) and point B(8, 8) as (y₁, y₂)

Distance AB = $\sqrt{(8-0)^2+(8--7)^2}$
Distance AB = $\sqrt{8^2+15^2}$
Distance AB = $\sqrt{289}$
Distance AB = 17

The line AB is dilated to A'B' by scale factor of 2, it means the length of the line is multiplied by 2

Distance A'B' = 2 × 17 = 34 units

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3 years ago

What is the solution to 5(4x-1.5x)+12-2

KIM [24]

Answer:

12.5x+10

Step-by-step explanation:

I'm assuming that you want to simplify this, because there is no equal sign.

If you want to simplify, first combine like terms.

First solve the first half of the equation: 20x-7.5x=12.5x

Now solve the second half of the equation: 12-2=10, so we have 12.5x+10.

That's your answer: 12.5x+10

8 0

3 years ago

Read 2 more answers

How to solve the equation 2x^2 -1 =5x?

Amanda [17]

<u>Answer:</u>

x = 2.68, x = -0.186

<u>Step-by-step explanation:</u>

We are given the following equation that we are to solve:

$2 x ^ 2 - 1 = 5 x$

Rearranging this quadratic equation to get:

$2 x ^ 2 -5 x - 1 = 0$

Solving it by using the quadratic formula as we cannot find any factors for it.

$x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5) \pm (-5)^2-4(2)(-1)}{2(2)}$

$x=\frac{5 \pm\sqrt{25+8} }{4}$

$x=\frac{5+\sqrt{33} }{4}$ , $x=\frac{5-\sqrt{33} }{4}$

x = 2.68, x = -0.186

7 0

3 years ago

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Given f(3)=9 and f(5)=28, using the first two terms of the Taylor series, the approximate value of f'(3) is (Keep 4 decimal poin

IrinaK [193]

Answer:

The approximation by Taylor series of f'(3) is 9.5000.

Step-by-step explanation:

Taking the two first terms for Taylor series gives the following expression:

$f(x)=f(x_{o})+f'(x_{o})*(x-x_{o})+e$

Where e represents the error of the approximation and in this case is of second order. For this particular example, it is no required to calculate.

Note that in the equation x is the independent variable, in contrast, xo is the value where all the derivatives of the function are calculated and must be defined. Observe that the value for the first derivative in x equal 3 is wanted to know, so xo will be equal 3.

Now to find f'(3) will use the rest of the information that was given:

f(5)=28 (x=5)

Replacing the previous values in the Taylor expansion:

$f(5)=f(3)+f'(3)*(5-3)$