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Digiron [165]
3 years ago
5

How to solve the equation 2x^2 -1 =5x?

Mathematics
2 answers:
Amanda [17]3 years ago
7 0

<u>Answer:</u>

x = 2.68, x = -0.186

<u>Step-by-step explanation:</u>

We are given the following equation that we are to solve:

2 x ^ 2 - 1 = 5 x

Rearranging this quadratic equation to get:

2 x ^ 2 -5 x - 1 = 0

Solving it by using the quadratic formula as we cannot find any factors for it.

x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}

x=\frac{-(-5) \pm (-5)^2-4(2)(-1)}{2(2)}

x=\frac{5 \pm\sqrt{25+8} }{4}

x=\frac{5+\sqrt{33} }{4}, x=\frac{5-\sqrt{33} }{4}

x = 2.68, x = -0.186

laila [671]3 years ago
4 0

Answer:

x = 2.68, x = -0.186 is the answer , i got a 100% on my test

Step-by-step explanation:

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