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GaryK [48]
3 years ago
11

Part C

Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0

Answer:

  see attached

Step-by-step explanation:

GeoGebra conveniently computes the point coordinates of the reflected points. In the attached, the reflections are done in the order listed in the table, so A' is reflected across x; A'₁ is reflected across y; A'₂ is reflected across y=x, and A'₃ is reflected across y=-x. The same notation is used for the other points. The values are listed in order, so you can copy them down the column in your table.

astra-53 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Plato

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\large\begin{array}{l} \textsf{Simplify the expression (I'm goint to call it E)}\\\\ \mathsf{E=\sqrt{4a-4}+\sqrt{a-1}} \end{array}


\large\begin{array}{l} \textsf{So E is a sum of two square roots. Notice that you can factor}\\\textsf{the 4 out on the first one:}\\\\ \mathsf{E=\sqrt{4\cdot a-4\cdot 1}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{4\cdot (a-1)}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{2^2\cdot (a-1)}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{2^2}\cdot \sqrt{a-1}+\sqrt{a-1}}\\\\ \mathsf{E=2\cdot \sqrt{a-1}+\sqrt{a-1}} \end{array}

\large\begin{array}{l} \mathsf{E=2\cdot \sqrt{a-1}+1\cdot \sqrt{a-1}}\\\\ \mathsf{E=(2+1)\cdot \sqrt{a-1}}\\\\ \boxed{\begin{array}{l}\mathsf{E=3\cdot \sqrt{a-1}} \end{array}} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2179170


\large\textsf{I hope this helps. :-)}


Tags: <em>square root sqrt simplify expression radical irrational algebra</em>

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Step-by-step explanation:

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Answer:

hope it helps

Step-by-step explanation:

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Plot the points (0,0) and (1,-2) on a coordinate plane.

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     (True)

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The points (1,2) and (1,3) are not in the solution set because,

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  (False)

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