Answer: y=6x-20 estimate: 250
Step-by-step explanation:
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
This is the equation for a circle! Start by grouping all the x terms together and do the same with the y terms so you get this: (x^2 - 14x) + (y^2 - 18y) + 105 = 0
Now move the 105 over to the other side to get it out of the way (it is part of the radius so it will be moved over there eventually anyway). Now we have:
(x^2 - 14x) +(y^2 - 18y) = -105. To complete the square on the x terms, take half the linear term (the 14) which is 7 and square it to get 49. That's what's added in to complete the square on the x's. But since you added it on the left, you also have to add it to the -105 on the right:
(x^2 - 14x + 49) + (y^2 - 18y) = -105 + 49 so far. Now do the same to the y terms by taking half of the linear term (the 18) and squaring it to get 81. That's what's added in on the left so it also has to be added in on the right:
(x^2 -14x + 49) + (y^2 - 18y +81) = -105 + 49 + 81. Simplifying all of this mess reduces to: (x-7)^2 + (y-9)^2 = 25 which is the equation of a circle with a center of (7, 9) and a radius of 5. Those are so much fun!
Answer:
6/16 is equivalent to 3/8 because after dividing the numerator (6) and denominator (16) we get 3/8.
Answer:
-10xsquared-x+38
Step-by-step explanation:
so,
general eqn of quadratic equation is,
axsquared+bx+c=y
where,
x and y are exchanged by coordinates given in qn
1,64a-8b+c=0
2,4a-2b+c=0
or c=2b-4a
60a-6b=0
3,36a-6b+c=8
32a-4b=8
