Answer:
Step-by-step explanation:
One of the more obvious "connections" between linear equations is the presence of the same two variables (e. g., x and y) in these equations.
Assuming that your two equations are distinct (neither is merely a multiple of the other), we can use the "elimination by addition and subtraction" method to eliminate one variable, leaving us with an equation in one variable, solve this 1-variable (e. g., in x) equation, and then use the resulting value in the other equation to find the value of the other variable (e. g., y). By doing this we find a unique solution (a, b) that satisfies both original equations. Not only that, but also this solution (a, b) will also satisfy both of the original linear equations.
I urge you to think about what you mean by "analyze connections."
To approximate the distance of points with three dimension, make use of the equation,
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2 +(z2 - z1)^2)
Substituting all the data from the points given,
<span>d = sqrt ((2 - -2)^2 + (-7 - 3)^2 +(4 - -5)^2) = sqrt 197
</span>
Thus, the distance from the points is approximately 14.04 and that is letter D.
Answer:
-8±10x
Step-by-step explanation:
you will follow BODMAS
B=bracket
O= off
D=division
M=multiplication
A=addition
S=subtraction
2×3=6
7×2=14
[6-14±10x-8]÷[x-2]
14±8=22
6-22=-16
[-16±10x]÷[x-2]=-8±10x
How many walls are there ?
what answers are shown to choose from ?
7.494 is the nearest thousandth
