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3 years ago

What is the value of n in the equation 0=18+128n^2?

Mathematics

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

$\large\boxed{\text{no soltion in the set of real numbers}}\\\boxed{n=-\dfrac{3}{8}i\ \vee\ n=\dfrac{3}{8}i\ \text{in the set of complex numbers}}$

Step-by-step explanation:

$18+128n^2=0\qquad\text{subtract 18 from both sides}\\\\128n^2=-18\qquad\text{divide both sides by 128}\\\\n^2=-\dfrac{18}{128}\\\\n^2=-\dfrac{18:2}{128:2}\\\\n^2=-\dfrac{9}{64}$

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Step-by-step explanation:

Given

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By comparing:

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