Answer:
Part A: 2k(2c2+5(2)-8c-20)
Part B: sorry i don't know how to do this part
Step-by-step explanation:
Part A, you divide each number by 2 first so you get a simplified version of each number. Then, you will quickly realize that the varible k is similar in all of the numbers then you remove that and put it with the 2 outside the (). Hope you understood my explination.
Answer:
yw
Step-by-step explanation:
look it up
Answer:
62
Step-by-step explanation:
The enclosing rectangle is 24 units long and 12 units high. Its area is ...
(24 units)(12 units) = 288 square units
The white circles obviously cover more than half the area, so the only viable answer choice is 62.
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If you want to go to the trouble to actually figure it out, you can find the area of each circle using the area formula ...
A = πr² = (3.14)(6²) = 113.04
Then both circles have an area of 2×113.04 = 226.08, and the shaded area is the difference between that and the rectangle area:
shaded area = 288 -226.08 = 61.92 ≈ 62
The dude on top of me is correct
This isn't the same problem but it's an idea. of what you're doing.
