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3 years ago

13

Tom Henderson takes out a $120,000 mortgage. He paid 1.6% of the loan amount in closing costs and $8,962.49 in total interest th

e first year of the loan.

1 answer:

Eva8 [605]3 years ago

5 0

119998.40 120000-1.60=119998.4 Hope I helped out some!!

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Como resuelvo 2x +8x.4x

Alex_Xolod [135]

Honestly photo math works for everything

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3 years ago

A can of grapefruit juice concentrate is 13 fluid oz. The recipe calls for a ratio of 2 cans of concentrate to 5 cans of cold wa

Assoli18 [71]

Answer:

You need a pitcher that can fit 91 fluid ounces.

Step-by-step explanation:

13 times 2 = 26

13 times 5 = 65

65 + 26 = 91

5 0

3 years ago

Read 2 more answers

If a theater holds 1800 and sells 1/3 of its seats how many tickets does it sell

kozerog [31]

Hey!

A theater holds 1,800 seats. It sells 1/3 of it. That means you have to find 1/3 of 1,800

$\frac{1800}{1} \times \frac{1}{3} = \frac{1800}{3} = 600$

<em>That means the theater sells 600 seats.</em>

$\framebox{Answer = 600 seats}$

7 0

4 years ago

The temperature during a winter day was less than –3 degrees Fahrenheit. Yuri wants to write an inequality for the temperature d

anyanavicka [17]

Answer:

The answer is t < -3

Step-by-step explanation:

t < -3 is the answer, because since the temperature is less than -3 degrees Fahrenheit it has to be t < -3

7 0

2 years ago

Read 2 more answers

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

So

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

So

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

3 years ago