When two values are given for a linear function, it is easier to obtain the equation using the two-point form, namely
(y-y1)=m(x-x1) where
m=slope=(y2-y1)/(x2-x1)
and
(x1,y1) and (x2,y2) are the given two points.
Here
(x1,y1)=(25,0.99), and
(x2,y2)=(100,3.99)
Find slope, m=(y2-y1)/(x2-x1)=(3.99-0.99)/(100-25)=3/75=0.04
Find equation:
(y-y1)=m(x-x1)
(y-0.99)=0.04(x-25)
Expand and simplify:
y=0.04x-1+0.99 , simplify
y=0.04x-0.01..............................Function that models the situation
Answer:
They will make 13.80 dollars
Step-by-step explanation:
so they made 1.80 more
Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20