Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
he first one and the third one
Step-by-step explanation:
Answer:
6x
Step-by-step explanation:
Step 1: Write equation
x + 2x + 3x
Step 2: Combine like terms
3x + 3x
6x
Answer:100
Step-by-step explanation:
