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Soloha48 [4]
3 years ago
10

A vertical line has points C, E, F from top to bottom. 2 lines extend from point E. One line extends to point A and another exte

nds to point B. Angle A E C is 90 degrees.
Given that Ray E B bisects ∠CEA, which statements must be true? Select three options.

m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
Mathematics
2 answers:
mariarad [96]3 years ago
7 0

Answer:

A.D.E

I GOT IT RIGHT IN EDG

nikdorinn [45]3 years ago
6 0

Answer:

ADE

Step-by-step explanation:

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The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

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3 years ago
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