Answer:
No, similar triangles cannot contain a pair of parallel lines. Yes, because || . Yes, because ∠QUR ≅ ∠TUS (vertical angles) and ∠R ≅ ∠S (alternate interior angles).
Step-by-step explanation:
Answer:
Center = (2,5)
Radius = 10
Choice A
To find this answer, first write the equation
(x-2)^2 + (y-5)^2 = 100
into
(x-2)^2 + (y-5)^2 = 10^2
Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
We see that (h,k) = (2,5) is the center
and r = 10 is the radius
Answer:
1/2
Step-by-step explanation:
cos(θ) = √(1 -sin(θ)²) = √(1 -3/4) = √(1/4)
cos(θ) = 1/2
Answer:
28
Step-by-step explanation:
this is a function
if h(x) is -8 you would plug it in for x:
-4(-8) -4 a negative × a negative is a positive
32- 4= 28
