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olya-2409 [2.1K]
3 years ago
7

I need help with number 2 don’t understand it. someone help plz.

Mathematics
2 answers:
Sholpan [36]3 years ago
8 0

I would say solve each diameter equation and order them fromleast to greatest, for example

1 Venus- 7.52×10 to the power of 3
So first simplify 10 to the power of 3 which is, 1000. Then you multiply 7.52 by 1000 which gets you 7520.

So solve each equation and order it

mr_godi [17]3 years ago
6 0
Neptune
Uranus
Earth
Venus
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Write a real-life word problem that corresponds to the equation below.
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The real life problem that corresponds to the equation will be "The area of a farmer's square garden is 144 square feet. What is the length of the garden?"

<h3>How to solve the equation</h3>

A real-life word problem that corresponds to the equation x² = 144 will be that the area of a farmer's square garden is 144 square feet. What is the length of the garden?

In this case, the length of the garden will be the square root of 144. This will be calculated thus:

x² = 144

x = ✓144

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Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

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Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

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