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Snezhnost [94]
4 years ago
14

The sum of three consecutive numbers is 72. What is the smallest of these numbers?

Mathematics
2 answers:
kodGreya [7K]4 years ago
8 0
The answer is 23 I think
WINSTONCH [101]4 years ago
7 0
If n stands for the smallest number, then the second and third number would be (n + 1) and (n + 2)

Write the equation based on what are given
the sum of three numbers = 72
n + (n + 1) + (n + 2) = 72

Then, solve the equation
n + (n + 1) + (n + 2) = 72
3n + 3 = 72
3n = 72 - 3
3n = 69
n = 69/3
n = 23

The smallest number is 23
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The polynomial p(x)=x^3+7x^2-36p(x)=x 3 +7x 2 −36p, left parenthesis, x, right parenthesis, equals, x, cubed, plus, 7, x, square
Iteru [2.4K]

Answer:

(x-2)(x+3)(x+6)

Step-by-step explanation:

Given the polynomial function p(x)=x^3+7x^2-36

We are to write it as a product of its linear factor

Assuming the value of x that will make the polynomial p(x) to be zero

Let x = 2

P(2) = 2³+7(2)²-36

P(2) = 8+7(4)-36

P(2) = 8+28-36

P(2) = 0

Since p(2) = 0 hence x-2 is one of the linear factors

Also assume x = -3

P(-3) = (-3)³+7(-3)²-36

P(-3) = -27+7(9)-36

P(-3) = -27+63-36

P(-3) = 36-36

P(-3) = 0

Since p(-3) = 0, hence x+3 is also a factor

The two linear pair are (x-2)(x+3)

(x-2)(x+3) = x²+3x-2x-6

(x-2)(x+3) = x²+x-6

To get the third linear function, we will divide x^3+7x^2-36 by x²+x-6 as shown in the attachment.

x^3+7x^2-36/x²+x-6 = x+6

Hence the third linear factor is x+6

x^3+7x^2-36 = (x-2)(x+3)(x+6)

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34kurt

Answer:

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Step-by-step explanation:

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4 years ago
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Answer:

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What is the least common denominator of 1/4 and 2/5?
bixtya [17]

Answer:

20

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