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romanna [79]
3 years ago
10

5.49 rounded to the nearest inetger

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0

Hey there! I'm happy to help!

Integers are numbers without decimals, or numbers you count. We see that 5.49 is between the integers 5 and 6, but it is closer to 5. The tenths place would have to be a 5 or larger to round up to 6.

Have a wonderful day! :D

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Planes Q and R are parallel. Explain how you know lines a and b are skew.
IrinaVladis [17]
By definition, skew lines are a pair of lines that are not parallel but do not intersect each other either. Hence, the conclusion would be, the lines are non-coplanar. An example would two random lines drawn in the x and y axes in a cartesian plane, respectively.
7 0
3 years ago
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you bought 5 chocolate bars and 8 blow pops for $23.25 your sister bought 2 chocolate bars and 13 blow pops for 21.55 how much d
kirza4 [7]

Answer:

  • $2.65

Step-by-step explanation:

Let chocolate bar = c and blow pops = b

<u>As per given we have equations below:</u>

  • 5c + 8b = 23.25
  • 2c + 13b = 21.55

<u>13 times the first equation minus 8 times the second to eliminate b and find c:</u>

  • 13(5c + 8b) - 8(2c + 13b) = 13(23.25) - 8(21.55)
  • 65c - 16c = 129.85
  • 49c = 129.85
  • c = 129.85/49
  • c = 2.65

Each chocolate bar costs $2.65

7 0
3 years ago
If anyone could help?
Trava [24]

Answer:

y=\frac{5}{7}x and y=\frac{7}{9}x

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In y=\frac{5}{7}x when x=3, y=15/4≈2.14

In y=\frac{3}{5}x when x=3, y=1.8

In y=\frac{7}{9}x when x=3, y≈2.33

In y=\frac{7}{11}x when x=3, y≈1.90

We can observe that in two cases, y=\frac{5}{7}x and y=\frac{7}{9}x, y is greater than 2.


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3 years ago
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Schach [20]

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7 0
2 years ago
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Explain how to graph the in inequality 8&gt;y
insens350 [35]

Answer:

How to Graph a Linear Inequality

First, graph the "equals" line, then shade in the correct area.

There are three steps:

1.) Rearrange the equation so "y" is on the left and everything else on the right.

2.) Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

4.) Shade above the line for a "greater than" (y> or y≥)  or below the line for a "less than" (y< or y≤).

Hope This Helps!    Have A Nice Day!!

8 0
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