The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
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0.75 or 3/4 that’s your answer as a decimal and fraction :)
I'm not 100% sure but I think this is how you solve it:
1. 800,000 x 0.06 = 48,000
2. 48,000 x 17 = 816,000
3. 800,000 + 816,000 = 1,616,000
The painting is worth $1,616,000 in 2017.
Answer:
88 adult tickets and 77 student tickets were sold.
Step-by-step explanation:
Let the number of adult tickets sold be 8x and the number of student tickets sold be 7x.
adult tickets + student tickets = 165 tickets
8x + 7x = 165
15x = 165
x = 165 ÷ 15
= 11
No. of adult tickets sold (8x) = 11 × 8
= 88
No. of student tickets sold (7x) = 11 × 7
= 77
