The greatest common factor of 12 and 15 is 3 because it is the greatest number divisible by both 12 and 15.
Answer: 0, π, 2π
Nevertheless, that is not an option. I see two possibilities: 1) the options are misswirtten, 2) the domain is not well defined.
If the domain were 0 ≤ θ < 2π, then 2π were excluded of the domain ant the answer would be 0, π.
Explanation:
1) The first solution, θ = 0 is trivial:
sin (0) - tan (0) = 0
0 - 0 = 0
2) For other solutions, work the expression:
sin(θ) + tan (-θ) = 0 ← given
sin (θ) - tan(θ) = 0 ← tan (-θ) = tan(θ)
sin(θ) - sin (θ) / cos(θ) = 0 ← tan(θ) = sin(θ) / cos(θ)
sin (θ) [1 - 1/cos(θ)] = 0 ← common factor sin(θ)
⇒ Any of the two factors can be 0
⇒ sin (θ) = 0 or (1 - 1 / cos(θ) = 0,
sin(θ) = 0 ⇒ θ = 0, π, 2π
1 - 1/cos(θ) = 0 ⇒ 1/cos(θ) = 1 ⇒ cos(θ) = 1 ⇒ θ = 0, 2π
⇒ Solutions are 0, π, and 2π
In fact if you test with any of those values the equation is checked. The only way to exclude one of those solutions is changing the domain.
Answer: a (see explanation below) .b.) rhombus .c) trapezoid in USA or trapezium elsewhere in the world
Step-by-step explanation:
For a.) Draw a horizontal from the bottom vertex, extending 2 units to the right. Then form a triangle by connecting a line from the right end of that line up to the right angle at the top of the original triangle
Answer:
40*
Step-by-step explanation:
the whole line FC would measure 180* so then 180-50 for AGC then AGB is congruent to EGD so 180-50-90---> 130-90---> 40* so angleBGC is 40 degrees
