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tia_tia [17]
3 years ago
8

ACME INC. is charged $2,500 plus $20 per hour by a company repairs their computers. If their budget for computer repair is $6,00

0, what is the maximum amount of hours of computer repair can they afford?
Mathematics
2 answers:
goldenfox [79]3 years ago
8 0
175 hours 
To do this subscript 2500 from 6000 and u get 3500 then divide that by 20 to get 175
fenix001 [56]3 years ago
5 0
Write an inequality expression based on the problem
$2,500 is a fixed cost, it will be the constant of the inequality. $20 is a variable cost because it changes every hour. For an instance, x hour is the maximum amount of hours. The inequality will be:
2,500 + 20x ≤ 6,000

Solve the value of x
2,500 + 20x ≤ 6,000

substract both sides by 2,500
2,500 - 2,500 + 20x ≤ 6,000 - 2,500
20x ≤ 3,500

divide both sides by 20
\dfrac{20x}{20} =  \dfrac{3,500}{20}
x ≤ 175
The maximum amount of hours is 175
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