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taurus [48]
3 years ago
15

How do I solve this.?

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0
I think you need to divide up each side with 4 and see what the answer is.
skad [1K]3 years ago
6 0
It is 443 1/3 because you divide it by 3

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Which of the following is a radical equation?<br> x+ √5 = 12<br> y2 = 16<br> 3+x7 = 13<br> 7VX = 14
cestrela7 [59]
The first one since the 5 has the radical symbol
3 0
4 years ago
Question 2 (1 point)
jonny [76]

Answer:

(2,4)

Step-by-step explanation:

Equation 1:

x+y=6(for the 6 times they scored)

x=-y+6

Equation 2:

7x+3y=26 (for the 7 point touchdowns, and 3 point field goals.)

7(-y+6)+3y=26(replace x with -y+6)

7y+42+3y=26(distrubite property)

-4y+42=26

-4y= -16

y= 4

Now that we know that y is equal to 4:

x+4=6

x=2

5 0
3 years ago
Read 2 more answers
How to round to the nearest dollar add or subtract
Setler [38]
Okay Abrahammontiel1, the thing you must remember is any thing that is 5 or over must be rounded up and anything lower must be rounded down.
Example:
$2.30
since we want to round to the nearest dollar we look at the digit behind the whole dollar, which in this case is 0.3
and since it's lower that 0.5 we must round down
So it will look like this: $2

If we had a number like $4.72
we would look at the 0.7
and since it is greater that 0.5 we would round  up so that it would equal $5

8 0
3 years ago
Hi, need help with solving this logarithm.​
vfiekz [6]

Answer:

\log 8 - \log x + 7\log\sqrt x =\log (8x^{\frac{5}{2}})

Step-by-step explanation:

Given

\log 8 - \log x + 7\log\sqrt x

Required

Express as a single expression

We have:

\log 8 - \log x + 7\log\sqrt x

Write 7 as an exponent

\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(\sqrt x)^7

Rewrite as:

\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(x^{\frac{1}{2}})^7

\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log x^\frac{7}{2}

Apply quotient and product rule of logarithm

\log 8 - \log x + 7\log\sqrt x =\log (\frac{8*x^\frac{7}{2}}{x} )

Apply law of indices

\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7}{2} - 1})

Solve exponent

\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7-2}{2}})

\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{5}{2}})

\log 8 - \log x + 7\log\sqrt x =\log (8x^{\frac{5}{2}})

8 0
3 years ago
Please help,Explain how solving -7y &gt; 161 is different from solving 7y &gt; -161.
Luden [163]

Answer:

-7y > 161

7y < -161

y < -23

7y > -161

y > -23

So, your answer is: -7y > 161 is equal to y < -23, and 7y > -161 is equal to y>-23.

Let me know if this helps!

6 0
3 years ago
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