Answer:


Step-by-step explanation:
step 1
Find the equation of the solid line
From the graph take the points (0,3) and (4,11)
Find the slope

The equation of the solid line in slope intercept form is equal to

we have

----> the y-intercept is the point (0,3)
substitute

therefore
The inequality is

step 2
Find the equation of the dashed line
The slope is given

From the graph take the y-intercept (0,-5)
The equation of the solid line in slope intercept form is equal to
we have

substitute

therefore
The inequality is

because the shaded region is below the dashed line
therefore
The system of inequalities is


when multiplying two binomials together we use the F.O.I.L. method:
First
Outer
Inner
Last
(7-3i)(2-i)
First: 7 * 2 ..... Outter: 7 * -i .... Inner: -3i * 2 ...... Last: -3i * -i
First: 14 ...... Outter= -7i ..... Inner: -6i .... Last: 3i^2
putting this together we get 14-7i-6i+2i^2
We combine like terms and end up with 2i^2-13i+14
Answer:

Step-by-step explanation:
Given equation is 
We need to find the value of 

Distribute
in the right-hand side

Add both sides 

Now, add both sides 

Divide both sides by 

So, 