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IceJOKER [234]
3 years ago
15

Choose the correct simplification of the quantity of x to the 7th power over y to the 9th power all raised to the 2nd power.

Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0
X to the 14th power over y to the 18th power is ur answer
Kipish [7]3 years ago
6 0

Answer:

Option 1 - x to the 14th power over y to the 18th power

Step-by-step explanation:

Given : The quantity of x to the 7th power over y to the 9th power all raised to the 2nd power.

To find : Choose the correct simplification of the quantity?

Solution :

The quantity of x to the 7th power i.e., x^7  .....(1)

Then the quantity y to the 9th power i.e.,  y^9 .....(2)

According to question,

Equation 1 is over equation 2,

i.e.,  \frac{x^7}{y^9}

And The resultant raised to the 2nd power.

i.e., (\frac{x^7}{y^9})^2

Simplify it by taking power inside, (x^a)^b=x^{a\times b}

\frac{x^{7\times 2}}{y^{9\times2}}

\frac{x^{14}}{y^{18}}

Which means x to the 14th power over y to the 18th power.

Therefore, Option 1 is correct.

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2 years ago
HELP.....................
Paha777 [63]

Let me first ask this :

how do u find the midnumber of 1 and 3 ?

( 1 + 3 ) ÷ 2 =

4 ÷ 2 =

2

_________________________________

It is the exact way we do to find the midpoint of a line ; have a look :

The midpoint of AB is P thus :

( Point A + Point B ) ÷ 2 = Point P

Suppose that we have point B as ( x , y ) then :

[ ( 2 , 3 ) + ( x , y ) ] ÷ 2 = ( 6 , - 1 )

Now we add the same components of points A and B together, that is, we add the first component A to the first component B and replace the first component, and so we add the second component A to the second component B. And replace the second component :

[ ( 2 + x , 3 + y ) ] ÷ 2 = ( 6 , - 1 )

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Well now we have a draw so the first components of both sides of the draw must be equal Also, the second components of the two sides of the equation must be equal , thus :

2 + x/2 = 6

Multiply both sides by 2

2 × ( 2 + x )/2 = 2 × 6

2 + x = 12

Subtract both sides 2

2 - 2 + x = 12 - 2

<h2>x = 10 </h2>

<h2>&</h2>

3 + y/2 = - 1

Multiply both sides by 2

2 × ( 3 + y )/2 = 2 × ( - 1 )

3 + y = - 2

Subtract both sides 3

3 - 3 + y = - 2 - 3

<h2>y = - 5 </h2>

________________________________

And finally, after all the hardship and misery, we realized that

<h2>B = ( 10 , - 5 ) </h2>

Which mean <em>O</em><em>p</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>C</em> is the correct answer.

And we're done...

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Step-by-step explanation:

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