For the answer to the question above, <span>what is the combined length of
the original line segment and its dilated image?
</span>RS = 10
image R'S' = 20
---> 10+20=30
I hope my answer helped you. Feel free to ask more questions. have a nice day!
I hope this helps ( there is no negatives )
Answer:
(final - initial/initial ) * 100
66 - 55/55 * 100
11/55 * 100
100/5
= 20 percent
Answer:
Divide both sides by 42 then reduce the fraction. The answer is 8/21=0.38
Step-by-step explanation:
Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!
