6:13 =83
6+13=19
1 part=83÷19
=4.37
6×4.4=26.4
13×4.4=57.2
26.4:57.2
p.s I got how much money only...
sorry
Usually you would have two to add, are you sure this is complete? If this is it then all you do is w-8w, which is -7w.
<h2>
Answer:</h2><h2>The partial products of (27) (108) are 216 , 0 , 27.</h2>
Step-by-step explanation:
To find the value of the second partial product 27x108,
Here the multiplicand = 27
The multiplier = 108
The partial products of the multiplication are :
(27) (8) = 0 2 1 6
(27) (0) = 0 0 0
(27) (1) = 2 7
Adding the terms, we get 2916.
The partial products are 216 , 0 , 27.
3x-x+2=4 thats the answer
We have from the angle bisector theorem that the sides AC and CD are proportional to AB and BD. Hence, we get the following equality that holds in general when the angles BAD and CAD are equal.
Substituting:
