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jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h. At 8.30a.m. Sipho left town A to trave

7nadin3 [17]

Answer:

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

$J(t) = 200 + 80t$

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

$S(t) = 100t$

At what time will Sipho catch up jabu?

He will catch up in t hours, and t is found when:

$S(t) = J(t)$

So

$100t = 200 + 80t$

$20t = 200$

$t = \frac{200}{20} = 10$

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm

4 0

3 years ago

Mrs. Adenan sold 63 bracelets at one craft fair and 36 bracelets at a second craft fair. Which expression correctly applies the

stellarik [79]

63 + 36...there is a common factor of 9
9(7 + 4) <== this is equivalent

63 + 36...there is a common factor of 3
3(21 + 12)...but this is not an answer choice...but it is equivalent

7 0

3 years ago

PLEASE HELP ME!!

antoniya [11.8K]

Since your slope is 3, (the number for slope is always right before x) and your y-intercept is one (that is always the number after the x) your answer would be B

4 0

3 years ago

PLEASE ANSWER QUICKLY I WILL MARK BRAINIEST AND 70 POINT

kykrilka [37]

a) You are given the rate as 7.4m/min,

The equation would become d = 7.4t where d is the total distance and t would be the total number of minutes.

b) d would be a positive number because the diver is ascending, which means he is moving up towards the surface.

c) To find how long it took the diver, replace d with 41.36 ( how deep the diver was) and solve for t:

41.36 = 7.4t

To solve for t, divide both sides by 7.4:

t = 41.36 / 7.4

t = 5.59 minutes ( 5 minutes and 35 seconds)

8 0

3 years ago

10 watermelons have an average weight of 4.3 pounds and 5 pumpkins have an average weight of 3.4 pounds. What is the average wei

bagirrra123 [75]

Since the average is the sum divided by the count, the sum is the average times the count.

So the sum of the weights of the watermelons is 10(4.3)=43 pounds.

The sum of the weights of the pumpkins are 5(3.4)=17 pounds

The sum of the weight of the fruits is 43+17=60 pounds

Dividing by 15 fruits gives an average item weight of 60/15 = 4 pounds

6 0

3 years ago

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Is what I did a correct step?If so, what is the next step?​

Is what I did a correct step?If so, what is the next step?