A.) For n independent variates with the same
distribution, the standard deviation of their mean is the standard
deviation of an individual divided by the square root of the sample
size: i.e. s.d. (mean) = s.d. / sqrt(n)
Therefore, the standard deviation of of the average fill volume of 100 cans is given by 0.5 / sqrt(100) = 0.5 / 10 = 0.05
b.) In a normal distribution, P(X < x) is given by P(z < (x - mean) / s.d).
Thus, P(X < 12) = P(z < (12 - 12.1) / 0.05) = P(z < -2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275
c.) Let the required mean fill volume be u, then P(X < 12) = P(z < (12 - u) / 0.05) = 1 - P(z < (u - 12) / 0.05) = 0.005
P(z < (u - 12) / 0.05) = 1 - 0.005 = 0.995 = P(z < 2.575)
(u - 12) / 0.05 = 2.575
u - 12 = 2.575 x 0.05 = 0.12875
u = 12 + 0.12875 = 12.12875
Therefore, the mean fill volume should be 12.12875 so that the probability that the average of 100 cans is below 12 fluid ounces be 0.005.
d.) Let the required standard deviation of fill volume be s, then P(X < 12) = P(z <
(12 - 12.1) / s) = 1 - P(z < 0.1 / s) = 0.005
P(z < 0.1 / s) = 1 - 0.005 = 0.995 = P(z < 2.575)
0.1 / s = 2.575
s = 0.1 / 2.575 = 0.0388
Therefore, the standard deviation of fill volume should be 0.0388 so that the probability that the average of 100 cans is below 12 fluid ounces be 0.005.
e.) Let the required number of cans be n, then P(X < 12) = P(z <
(12 - 12.1) / (0.5/sqrt(n))) = 1 - P(z < (12.1 - 12) / (0.5/sqrt(n))) = 0.01
P(z < 0.1 / (0.5/sqrt(n))) = 1 - 0.01 = 0.99 = P(z < 2.327)
0.1 / (0.5/sqrt(n)) = 2.327
0.5/sqrt(n) = 0.1 / 2.327 = 0.0430
sqrt(n) = 0.5/0.0430 = 11.635
n = 11.635^2 = 135.37
Therefore, the number of cans that need to be measured such that the average fill volume is less than 12 fluid ounces be 0.01
Answers
b = 2.77 m
A = 43.0°
C = 111.1°
cosine law to find b
b = 2.7708\ m
Find angle A with sine law
![\displaystyle \frac{\sin A}{a} = \frac{\sin B}{b} \\ \\ \sin A = \frac{a \sin B}{b} \\ \\ A = \sin^{-1} \left[ \frac{a \sin B}{b} \right] \\ \\ A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708} \right] \\ \\ A = 43.0467020](https://tex.z-dn.net/?f=%5Cdisplaystyle%0A%5Cfrac%7B%5Csin%20A%7D%7Ba%7D%20%3D%20%5Cfrac%7B%5Csin%20B%7D%7Bb%7D%20%5C%5C%20%5C%5C%0A%5Csin%20A%20%3D%20%5Cfrac%7Ba%20%5Csin%20B%7D%7Bb%7D%20%5C%5C%20%5C%5C%0AA%20%3D%20%5Csin%5E%7B-1%7D%20%5Cleft%5B%20%5Cfrac%7Ba%20%5Csin%20B%7D%7Bb%7D%20%20%5Cright%5D%20%5C%5C%20%5C%5C%0AA%20%3D%20%5Csin%5E%7B-1%7D%20%5Cleft%5B%20%5Cfrac%7B4.33%20%5Csin%2025.9%7D%7B2.7708%7D%20%20%5Cright%5D%20%20%5C%5C%20%5C%5C%0AA%20%3D%2043.0467020)
Find C with angles in triangle sum to 180
A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
Answer:
x-intercept - x = 1/2y - 3.15
y-intercept - y = 2x + 6.3
Step-by-step explanation:
For x,
-6x + 3y = 18.9
-6x = -3y + 18.9
x = -3y/-6 + 18.9/-6
x = 1/2y - 3.15
For y,
-6x + 3y = 18.9
3y = 6x + 18.9
y = 6x/3 + 18.9/3
y = 2x + 6.3
Answer:
0.2x+3
Step-by-step explanation:
Answer:
Tangent segment ? I think. I don't know for sure because of the way you wrote the question- I got a bit confused.
