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matrenka [14]
2 years ago
7

Which equation can we use to solve the following? 42 · X = 16

Mathematics
2 answers:
Kazeer [188]2 years ago
4 0

Answer:

Divide both sides by 42 then reduce the fraction. The answer is 8/21=0.38

Step-by-step explanation:

romanna [79]2 years ago
3 0
The equation is 42/16=x
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The square below represents one whole
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Answer:

Fraction: 23/100

Decimal: 0.23

Percent: 23%

Step-by-step explanation:

Hope this helps!

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Write .5834 in Scientific Notation.
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5.834 x 10 to the power of -1
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If ABC is a right triangle with B the right angle, A=(-3,2) and B =(2,5), find possible
ahrayia [7]

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3 years ago
Elizabeth runs a farm stand that sells apples and raspberries. Each pound of apples sells for $2.25 and each pound of raspberrie
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2 years ago
An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.
Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0
2 years ago
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