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3 years ago

HELP PLEASE! Thankkkkkk youuuuu❤️

Mathematics

1 answer:

inysia [295]3 years ago

8 0

Answer:

14 is a line and 18 is none.

Step-by-step explanation:

I LIKE TURTLES!

YAYAYAYAYAYAYA TURTLES!

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Which expression is the difference with 2 terms

erastovalidia [21]

B, 6x -9. the rest either contain two many terms or use a different operation. hope this helps x

6 0

3 years ago

Unknown angle problems (with algebra)

lubasha [3.4K]

Answer: x = 20 degree
3x = 3×20 which is 60 degree
And the other one is 100 degree
Add all the number 100+60+20 degree is 180 degree

7 0

3 years ago

Help please.. look at the image...

vova2212 [387]

Answer: 195 = 35x + 20

Step-by-step explanation: This follows the y = mx + b formula.

y is your total, what the equation equals, and in this case it is your total cost of $195.

x is your independent variable, and time is always independent. When m is $35, you can plug in any hour (time!) for the x.

b is your initial value. This is what you start with, and in this case, it is your $20 equipment fee. You KNOW you have to pay that.

Hope this helps!

4 0

4 years ago

Here are five number cards . 2,5,7,8,9 . One of the cards is removed and the mean average of the remaining four number cards is

Elodia [21]

Answer:

Step-by-step explanation:

Given that there are 5 number cards.

They are 2,5,7,8,9

Total of all numbers in the cards = 2+5+7+8+9= 31

One card is removed say with number x.

Now sum new would be =31-x .. i

Average of remaining 4 cards = 6

So sum of remaining 4 cards = 6(4) = 24 ... ii

i and ii represent the sum of remaining 4 cards. Hence they should be equal

31-x =24

Subtract 31 from both sides to get

-x=-7

Or x =7

7 0

4 years ago

The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris a

nadezda [96]

Answer and explanation:

Given : The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively.

The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively.

Let the event E denote the poor print quality.

Let the event A be the no printer problem i.e. P(A)=0.8

Let the event B be the misaligned paper i.e. P(B)=0.02

Let the event C be the high ink viscosity i.e. P(C)=0.08

Let the event D be the printer-head debris i.e. P(D)=0.1

and the probabilities of poor print quality given printers are

$P(E|A)=0,\ P(E|B)=0.3,\ P(E|C)=0.4,\ P(E|D)=0.6$

First we calculate the probability that print quality is poor,

$P(E)=P(A)P(E|A)+P(B)P(E|B)+P(C)P(E|C)+P(D)P(E|D)$

$P(E)=(0)(0.8)+(0.3)(0.02)+(0.4)(0.08)+(0.6)(0.1)$

$P(E)=0+0.006+0.032+0.06$

$P(E)=0.098$

a. Determine the probability of high ink viscosity given poor print quality.

$P(C|E)=\frac{P(E|C)P(C)}{P(E)}$

$P(C|E)=\frac{0.4\times 0.08}{0.098}$

$P(C|E)=\frac{0.032}{0.098}$

$P(C|E)=0.3265$

b. Given poor print quality, what problem is most likely?

Probability of no printer problem given poor quality is

$P(A|E)=\frac{P(E|A)P(A)}{P(E)}$

$P(A|E)=\frac{0\times 0.8}{0.098}$

$P(A|E)=\frac{0}{0.098}$

$P(A|E)=0$

Probability of misaligned paper given poor quality is

$P(B|E)=\frac{P(E|B)P(B)}{P(E)}$

$P(B|E)=\frac{0.3\times 0.02}{0.098}$

$P(B|E)=\frac{0.006}{0.098}$

$P(B|E)=0.0612$

Probability of printer-head debris given poor quality is

$P(D|E)=\frac{P(E|D)P(D)}{P(E)}$

$P(D|E)=\frac{0.6\times 0.1}{0.098}$

$P(D|E)=\frac{0.06}{0.098}$

$P(D|E)=0.6122$

From the above conditional probabilities,

The printer-head debris problem is most likely given that print quality is poor.

3 0

3 years ago

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