Answer:
Step-by-step explanation:
1) The equation of a line is given by y = mx + c, where m = slope or gradient and c is intercept on y - axis. Given in this question, m = -5 and c = 3. Subtituting this in the equation y = mx + c, we have y = -5x + 3, therefore, the equation of the line is y = -5x + 3 or y + 5x = 3
2) The equation of a line is given as y-y1 = m(x-x1), where x1 = 6, y1 = -4 and m = -1/3. The equation of the line is y - -4 = -1/3(x - 6)
y+4 =-1/3(x-6)
3(y+4)= -1(x-6)
3y + 12 = -x+6
x+3y=6-12
x+3y= -6, therefore the equation of the line is x+3y = -6
3) The equation is y-y1=m(x-x1), where m=(y2-y1)/(x2-x1)=
(2- -4)/(-2-0)=6/-2=-3
y- -4= -3(x-0)= -3x
y+4= -3x
y+3x= -4
4) y-y1=m(x-x1)
m=(2-1) /(-4- -6)=1/2
y-1=1/2(x- -6)
y-1=1/2(x+6)
2(y-1) = x+6
2y-2=x+6
2y-x =6+2=8 2y-x=8
5) The equation is with undefined slope passing through (2, 5) is
x-2=0
x=2
