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4 years ago

Please help quick.. I’ve been stuck on this no matter what answer I have

Mathematics

1 answer:

Aleonysh [2.5K]4 years ago

5 0

Answer:

10 should be the answer

Step-by-step explanation:

Im not sure if its correct but if you stick to powers of ten you should get 10

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HELP ME PLZ!!!! if the answer is right ill mark you brainliest

STALIN [3.7K]

Answer:

9.6558916e+17

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

= 9.26 × 1010

(scientific notation)

= 9.26e10

(scientific e notation)

= 92.6 × 109

(engineering notation)

(billion; prefix giga- (G))

its probably: 9.26 × 1010 as the question asks for scientific notation

Step-by-step explanation:

somewhere between those lines, good luck!

5 0

3 years ago

What is the value of A when we rewrite<br> (5/2)^x +(5/2)^x+3 as A x (5/2)^x

elixir [45]

Answer:

Step-by-step explanation:

$(\frac{5}{2})^{x}+(\frac{5}{2})^{(x+3)}=(\frac{5}{2})^{x}+(\frac{5}{2})^{x}*(\frac{5}{2})^{3}\\\\=(\frac{5}{2})^{x}*[1+(\frac{5}{2})^{3}]$

Therefore,

$A=1+(\frac{5}{2})^{3}$

3 0

3 years ago

Find the difference quotient of f(x)=5x+4

Aleonysh [2.5K]

The differnce quotient is basically taking the derivitive (result will be f'(x)=5, but anyway)

here is the disffernce quotient
$lim_{h\rightarrow0}\frac{f(x+h)-f(x)}{h}$

so
for your equation
$lim_{h\rightarrow0}\frac{(5(x+h)+4)-(5x+4)}{h}$
$lim_{h\rightarrow0}\frac{5x+5h+4-5x-4}{h}$
$lim_{h\rightarrow0}\frac{5h}{h}$
h's cancel and you are left with 5
the differnce quotient is 5

6 0

3 years ago

What is the missing constant term in the perfect square that starts with x 2 − 16 x

OlgaM077 [116]

Explanation:

Divide the negative 16 by 2= -8

Then square -8

So the missing constant is 64

The perfect square would be (x-8)^2

7 0

3 years ago

The sum of six times a number and thirteen is five less than the product of three and the number

Svetllana [295]

Answer:

1 and 1/3

Step-by-step explanation:

I got this because you can first take 13-5 which is 8 then you can divide 8 by 6 to get your final answer.

Hope this helps.

6 0

3 years ago