Product tan1°.tan2°.tan3º......tan89° is:

1 answer:

4 0

$\sin(x) = \cos(90-x) \frac{sin(x)}{cos(90-x)} = 1\\\prod_{n=1}^{89}\tan(n) = \frac{\sin(1)}{\cos(1)} \cdot \frac{sin(2)}{cos(2)}...\frac{sin(89)}{cos(89)} = 1$

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Add them together thee we j get your answer

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Answer:

1: $y=-1x-3$

2: $y=0.8x+4.2$

3: $y=2x-3$

Step-by-step explanation:

Question 1: When lines are parallel, that means they're slope is the same and there y-intercept is different. So the first step is to calculate the slope of BC. If you look at BC you'll notice it goes down by 2 and goes forward by 2 so the slope is -2/2 or -1. This completes one part of the slope-intercept form which is y=mx+b where m is the slope and b is the y-intercept. The y-intercept will be calculated using the point A. since the equation passes through point A

-1 = (-2)(-1) + b

-1 = 2 + b

-3 = b

y=-1x-3

Question 2: Same concept here, if you look at AC, you'll see it "rises" by 4 and "runs" by 5, thus the slope is 4/5. Since it passes through B we'll use that to find the y-intercept

5 = (4/5)(1) + b

5 = 4/5 + b

b = 4.2

Question 3: It "rises" by 6 and "runs" by 3, thus the slope is 6/3 which is 2.

Plug in known values

3=(3)(2) + b

3 = 6 + b

-3 = b

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