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3 years ago

Product tan1°.tan2°.tan3º......tan89° is:

1 answer:

4 0

$\sin(x) = \cos(90-x) \frac{sin(x)}{cos(90-x)} = 1\\\prod_{n=1}^{89}\tan(n) = \frac{\sin(1)}{\cos(1)} \cdot \frac{sin(2)}{cos(2)}...\frac{sin(89)}{cos(89)} = 1$

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Martha Washington walks 30 minutes each day. If she walks for 140 days, how many hours will she walk?

telo118 [61]

make 30 minutes into an hour then divide 140 by 2

140/2=70

70x1=70

5 0

2 years ago

Convert 9.3 kribs into grees given that 4.2 kribs = 18 grees.

maria [59]

Answer:

39.9 grees

Step-by-step explanation:

Since 4.2 kribs = 18 grees

Then,

1 krib = 18/4.2 grees

9.3 kribs = (18/4.2) x 9 3

9.3 kribs = 39.9 grees.

4 0

3 years ago

Find the 12th term of the geometric sequence 1, -4, 16,

Korvikt [17]

Answer:

a₁₂ = - 4194304

Step-by-step explanation:

the nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

here a₁ = 1 and r = $\frac{-4}{1}$ = - 4 , then

a₁₂ = 1 × $(-4)^{11}$ = - 4194304

8 0

3 years ago

Word problem

Vlad [161]

Answer:

p=2

Step-by-step explanation:

4.05p+14.40=4.50(p+3) < equation

4.05p+14.40=4.50p+13.50 < multiply

14.40=.45p+13.50 < subtract

.9=.45p < subtract

2=p < divide

5 0

3 years ago

Read 2 more answers

What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

Ratling [72]

we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

$(30 a^{2+k})(b^{3+1})$

$30a^{2+k}b^{4}$

now, we can equate it with right side

and we get

$30a^{2+k}b^{4}=30a^6 b^4$

We can see that both sides have 30 , a and b

and they are equal

so, exponent of a must also be equal

$2+k=6$

now, we can solve for k

$2+k-2=6-2$

$k=4$ ................Answer

3 0

3 years ago

Read 2 more answers