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3 years ago

Product tan1°.tan2°.tan3º......tan89° is:

1 answer:

4 0

$\sin(x) = \cos(90-x) \frac{sin(x)}{cos(90-x)} = 1\\\prod_{n=1}^{89}\tan(n) = \frac{\sin(1)}{\cos(1)} \cdot \frac{sin(2)}{cos(2)}...\frac{sin(89)}{cos(89)} = 1$

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2 years ago

Pay the bill using the fewest possible bills/coins

marysya [2.9K]

Answers:

Open the pdf below and youll find what you need. also do the largest bills you can.

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2 years ago

Find the indicated function value for csc -450°

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3 years ago

F(x)=5x^4 helllllpppppp

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we can use properties of functions to find this out

for $f(x)=ax^b$

if b is even, then the ends of the function go in the same directions (both up or both down)

if b is odd, then the ends of the function go in different directions (one up and one down)

if a is positive and b is even, then both ends point up

if a is positve and b is odd, then it goes from bottom left to top right

if a is negative and b is even, then both ends point down

if a is negative and b is odd, then it goes from top left to bottom right

given $f(x)=5x^4$

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so it has both ends pointing up

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2 years ago

Oh no! Thomas is lost in the GGBL building after an exam, and trying to get out. Thereare four identical hallways leading away f

Brums [2.3K]

Answer:

Check the explanation

Step-by-step explanation:

Since each and every one of the 4 hallways is equally likely then

$P(H1)=1/4P(H2)=1/2P(H3)=1/4$

Now, if he chooses H1 he escapes after 12 minutes then

$E(T|H1)=12$

If he chooses H2 then he wastes 10 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H2)=10+E(T)$

Analogously, if he chooses H3 then he wastes 40 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H3)=40+E(T)$

Therefore

$E(T) = E(T|H1)P(H1) + E(T|H2)P(H2) + E(T H3)P(H3) = (12) + (E(T) +10) + (E(T) + 40) = 3+ *E(T)+5+ 10 = E(T) +18 CON A'$

So we have

$E(T) = E(T) + 18 E(T) = 18 E(T) = 4(18) = 72$

Therefore he is expected to escape in 72 minutes

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3 years ago