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Crazy boy [7]
3 years ago
9

12-3b<9 in solving the inequalities

Mathematics
1 answer:
Dimas [21]3 years ago
3 0
12 - 3b < 9

12 (-12) - 3b < 9 (-12)

-3b < -3

-3b/-3 < -3/-3

(note when dividing a negative number, flip the inequality sign)

b > 1 is your answer

hope this helps
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Express the confidence interval (0.036, 0.086) in the form of p-e&lt; p
lina2011 [118]

Answer:

p-e< p < p+e

(0.061 - 0.025) < 0.061 < (0.061 + 0.025)

0.036 < 0.061 < 0.086

Step-by-step explanation:

Given;

Confidence interval CI = (a,b) = (0.036, 0.086)

Lower bound a = 0.036

Upper bound b = 0.086

To express in the form;

p-e< p < p+e

Where;

p = mean Proportion

and

e = margin of error

The mean p =( lower bound + higher bound)/2

p = (a+b)/2

Substituting the values;

p = (0.036+0.086)/2

Mean Proportion p = 0.061

The margin of error e = (b-a)/2

Substituting the given values;

e = (0.086-0.036)/2

e = 0.025

Re-writing in the stated form, with p = 0.061 and e = 0.025

p-e< p < p+e

(0.061 - 0.025) < 0.061 < (0.061 + 0.025)

0.036 < 0.061 < 0.086

6 0
4 years ago
Which of the following is an equivalent form for 2x=log3(y-1)
skad [1K]

Answer:

B

Step-by-step explanation:

2x = log3 (y - 1)

y - 1 = 3^2x

y = 3^2x +  1

8 0
3 years ago
Factorize <br>A 3x⁴-3<br>B 16y²-1<br>C x⁵-4x³​
Y_Kistochka [10]

Answer:

Step-by-step explanation:

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3 years ago
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The mean weight of frozen yogurt cups in an ice cream parlor is 8 oz.Suppose the weight of each cup served is normally distribut
vaieri [72.5K]

Answer:

10.03% probability of getting a cup weighing more than 8.64oz

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 8, \sigma = 0.5

What is the probability of getting a cup weighing more than 8.64oz

This is the 1 subtracted by the pvalue of Z when X = 8.64. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.64 - 8}{0.5}

Z = 1.28

Z = 1.28 has a pvalue of 0.8997

1 - 0.8997 = 0.1003

10.03% probability of getting a cup weighing more than 8.64oz

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3 years ago
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