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ycow [4]
3 years ago
14

Find the 6th term of the following geometric sequence: 2, 8, 32, 128, ...

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer: 2048

Step-by-step explanation: u have to multiply each term by 4

Nadusha1986 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

t1 = 2= 2 * 4 ^ 1 -1

t2 = 8= 2* 4^2-1

t3 = 32= 2 * 4^3 -1

t4 = 128 = 2* 4^ 4 -1

----------------------------

tn = 2 * 4^ (n - 1)

Now

the 6th term of the sequence is

t6 = 2 * 4^ 6 -1

    = 2 * 1024

    = 2048

hope it was helpful.

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Solve x2 - 8x - 9 = 0. Rewrite the equation so that it is of the form x2 + bx = c.
barxatty [35]

Answer:

x=9,-1  and x^2+(-8)x=9

Explanation:

we have been given with the quadratic equation x^2-8x-9

we compare the given quadratic equation with general quadratic equation

general quadratic is ax^2+bx+c=0

from given quadratic equation a=1,b= -8,c= -9

substituting these values in the formula for discriminant D=b^{2}-4ac

D=(-8)^2-4(1)(-9)=100

Now, to find the value of x

Formula is x=\frac{-b\pm\sqrt{D}}{2a}

Now, substituting the values we will get

x=\frac{-(-8)\pm\sqrt{100}} {2}= \frac{8\pm10}{2}=9,-1

And rewritting the given equation by  shifting 9 to right hand side of the given equation and taking minus inside the bracket so as to convert it in the form of

x^2+bx=c

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bulgar [2K]

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Which statements are true about the polynomial 4x3 – 6x2 + 8x – 12?
olga2289 [7]

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2. correct- factor: 4

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KiRa [710]

Answer:

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Alternate Hypothesis, H_A : \mu < 1,100 square feet

Step-by-step explanation:

We are given that the mean area of several thousand apartments in a new development is advertised to be 1,100 square feet.

A consumer advocate has received numerous complaints that the apartments are smaller than advertised.

<u><em>Let </em></u>\mu<u><em> = mean area of several apartments.</em></u>

So, Null Hypothesis, H_0 : \mu = 1,100 square feet

Alternate Hypothesis, H_A : \mu < 1,100 square feet

Here, <u>null hypothesis states that</u> the mean area of apartments are same as advertised.

On the other hand, <u>alternate hypothesis states that</u> the mean area of apartments are smaller than advertised.

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