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ycow [4]
3 years ago
14

Find the 6th term of the following geometric sequence: 2, 8, 32, 128, ...

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer: 2048

Step-by-step explanation: u have to multiply each term by 4

Nadusha1986 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

t1 = 2= 2 * 4 ^ 1 -1

t2 = 8= 2* 4^2-1

t3 = 32= 2 * 4^3 -1

t4 = 128 = 2* 4^ 4 -1

----------------------------

tn = 2 * 4^ (n - 1)

Now

the 6th term of the sequence is

t6 = 2 * 4^ 6 -1

    = 2 * 1024

    = 2048

hope it was helpful.

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A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
Three fourths of college students use the Internet more than the library. Nine hundredths use the library more. How many times m
Leno4ka [110]
Division
4/3X 100/9 = 8 1/3
5 0
3 years ago
7(1 - 76) - 2b = -197
noname [10]

Answer:

b= -164

Step-by-step explanation:

calculate the difference

7x(-75)-2b= -197

multiply the numbers

-525-2b= -197

move the constant to the right- hand side and change the sign

-2b= -197+525

add

-2b=328

divide

b= -164

4 0
3 years ago
The formula for the nth term of an arithmetic sequence can be found using the formula a Subscript n Baseline = a Subscript 1 Bas
Gnoma [55]

The equation of nth term will be written as for n as will be (\rm a_n - a₁ + d) / d. Then the correct option is D.

The missing options are attached to the picture given below.

<h3>What is a sequence?</h3>

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The formula for the nth term of an arithmetic sequence can be found using the formula given below.

\rm a_n = a_1 + (n-1)d

Then arrange the equation for n, we have

\begin{aligned} \rm a_n - a_1 & \rm = nd - d\\\\\rm a_n - a_1 + d & \rm =nd\\\\\rm n & \rm = \dfrac{a_n - a_1 + d}{d}  \end{aligned}

Then the correct option is D.

More about the sequence link is given below.

brainly.com/question/21961097

#SPJ1

6 0
2 years ago
Please help! 37. A and B
Volgvan

Answer:

a

Step-by-step explanation:

mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

6 0
2 years ago
Read 2 more answers
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