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3 years ago

You can spend no more than $100 on a party you are hosting the cost per guest is eight dollars what is the number of the guests

Mathematics

2 answers:

Levart [38]3 years ago

5 0

Answer:

Step-by-step explanation:

100÷8=12.5

can't have half of a person

Amiraneli [1.4K]3 years ago

3 0

Answer:

its.12.5

Step-by-step explanation:

but if you round it up it can be either 13 or 12 but i would stick with 12 cause you cant round it up for guests since you know real life and if you stay at 12 they hey stay at 12

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which expression is equivalent to (^3sqrtm)^7 in exponential form? a) 7 m/3 b) 3 m/7 c) m 3/7 d) m 7/3

Komok [63]

$(\sqrt[3]{m})^{7} = m^{ \frac{7}{3}}$

5 0

3 years ago

If the function rule is 5x, what is the value when x=4

OleMash [197]

20 will be the answer when x=4

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3 years ago

5x-3y-2(4x-y) Can someone help

Lisa [10]

Answer:

-3x-1y

Step-by-step explanation:

5x - 3y⇒ -2(4x-y)

⇒-2(4x - y) = -8x +2y

5x - 3y -8x + 2y

Combine like terms:

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-3x - 1y

8 0

3 years ago

What is the equation of the line passing through the points (Two-fifths, StartFraction 19 Over 20 EndFraction)and (one-third,

Vinil7 [7]

<h3>4x - 8y = -6 is the equation of line in standard form</h3>

Solution:

The equation of line in point slope form is given as:

$y - y_1 = m(x-x_1)$

Where, m is the slope of line

The slope of line is given as:

$m = \frac{y_2-y_1}{x_2-x_1}$

From given,

$(x_1, y_1) = (\frac{2}{5} , \frac{19}{20})\\\\(x_2, y_2) = (\frac{1}{3} , \frac{11}{12})$

Substituting the values we get,

$m = \frac{\frac{11}{12} - \frac{19}{20}}{\frac{1}{3} - \frac{2}{5}}\\\\Simplify\\\\m = \frac{-8}{240} \times \frac{15}{-1}\\\\ m = \frac{120}{240}\\\\m = \frac{1}{2}$

$\text{Substitute } m = \frac{1}{2} \text{ and } (x_1, y_1) = (\frac{2}{5} , \frac{19}{20}) \text{ in eqn 1 }$

$y - \frac{19}{20} = \frac{1}{2}(x - \frac{2}{5})\\\\y - \frac{19}{20} = \frac{x}{2} - \frac{1}{5}\\\\\frac{x}{2} - y = - \frac{19}{20} + \frac{1}{5}\\\\\frac{x}{2} - y = \frac{-15}{20}\\\\Simplify\\\\y = \frac{1}{2}x + \frac{3}{4}$