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podryga [215]
3 years ago
13

(10pts) Ivan bought three games and paid $65 for all three. The second game was 50% more expensive than the first one. The price

of the third game was 50% of the price of the second game. Find the price of the first game.
PLSSSSSSSS HELPPPP NOWWWWWW!!!







Answer:

The price of the first game is $.
Mathematics
1 answer:
lutik1710 [3]3 years ago
3 0

We are required to find the price of the first game

The price of the first game is $20

Given:

let

price of the first game = x

price of the second game = x + 50% of x

= x + 0.5x

= 1.5x

Price of the third game = 50% of 1.5x

= 0.5 × 1.5x

= 0.75x

Total cost of game = $65

<em>Total cost of game = price of the first game + price of the second game + Price of the third game</em>

65 = x + 1.5x + 0.75x

65 = 3.25x

divide both sides by 3.25

x = 65 ÷ 3.25

x = 20

Therefore, the price of the first game is $20

Read more:

brainly.com/question/291220

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Leviafan [203]
Tony has 24 books in total because if 1/8 of the books are mystery and there are 8 mystery books you have to multiple the denominator by the amount of mystery books (8*3=24). 
8 0
3 years ago
Write an equation of the line that passes through (2,-4) and (0,-4)
Arte-miy333 [17]

y = mx + b

To find the slope(m), you use the slope formula:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

You plug in the points into the equation.

m = \frac{-4 - (-4)}{0 - 2}

m = \frac{-4+4}{0-2} = \frac{0}{-2} =0

The slope is 0

y = 0x + b

Any number multiplied by 0 is 0. So:

y = b

To find b, you plug in the y value of either of the points.

-4 = b

Your equation is:

y = -4 (This is a horizontal line)

5 0
3 years ago
In ΔEFG, the measure of ∠G=90°, the measure of ∠E=6°, and GE = 71 feet. Find the length of EF to the nearest tenth of a foot.
djyliett [7]

Answer:68.2

Step-by-step explanation:

cos6=71/EF

cos6= 0.960170286650366

0.960170286650366= 71/EF

0.960170286650366*71=EF

EF= 68.2

3 0
3 years ago
Read 2 more answers
From Mississippi Solo Book:
Ede4ka [16]
...........................................
3 0
2 years ago
Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

8 0
2 years ago
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