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gogolik [260]
3 years ago
14

At noon joyce drove to the lake at 30 mph, but she made the long walk back home at 4 mph. how many hours did she walk if she was

gone for 17 hours
Mathematics
1 answer:
lina2011 [118]3 years ago
4 0
By definition we have the following equation:
 t = d / v
 Where,
 t: time
 d: distance
 v: speed
 For this case we have:
 d / 30 + d / 4 = 17
 Rewriting we have:
 2d + 15d = 17 (60)
 17d = 17 (60)
 d = 60 mi
 Then, the walking time is
 t = d / v
 t = 60/4
 t = 15 hours
 Answer:
 
She walked
 
t = 15 hours
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The zeros of the function are , 3, and , and the y-intercept of the function is located at .
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(x+2)=0

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PLS HELP 50 POINTS<br><br> Calculate m∠ABC and m∠CBD, what is the value of x?
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An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t
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Answer:

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

\bar X=52.8 represent the sample mean  for the MPG of the cars

\sigma=1.6 represent the population standard deviation

n=250 sample size  of cars

\mu_o =52.6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:  

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

Replacing we have this:

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

Decision

Since is a two tailed test the p value would be:  

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

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3 years ago
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