All categories

3 years ago

Man I'm having so much trouble

Mathematics

2 answers:

BARSIC [14]3 years ago

5 0

Are you finding slope because i use a app called math warehouse search up and use the slope calculator it helps!!

defon3 years ago

4 0

Answer:

if only i was smarter

Step-by-step explanation:

Example

You might be interested in

1.What is the core characteristic that defines a zero-based budget?

lakkis [162]

Answer:

1. You account for every dollar you make to where your budget shows you have $0

2. She will have $125 leftover to budget out as she sees fit

3. If she does not account for it she may over spend or think she has extra money

4. I would put it in savings

5. No this is not what it means. This means that your paycheck will be able to cover your expenses.

6. You should put extra money in savings. You never know what will occur and savings can always help.

Step-by-step explanation:

7 0

3 years ago

Zack spent $150 for 3tickets what was the ratio of money to tickets

Tcecarenko [31]

$50 each.................... hope it helped

4 0

3 years ago

(a) Write a pair of negative integers whose difference gives 8

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

-8 ; -16

Difference = -8 - (-16) = -8 + 16 = 8

4 0

3 years ago

Find an equation of the circle that satisfies the given conditions. (Give your answer in terms of x and y.) Center at the origin

Elanso [62]

Answer:

The equation of circle is $x^2+y^2=65$ .

Step-by-step explanation:

It is given that the circle passes through the point (8,1) and center at the origin.

The distance between any point and the circle and center is called radius. it means radius of the given circle is the distance between (0,0) and (8,1).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula the radius of circle is

$r=\sqrt{\left(8-0\right)^2+\left(1-0\right)^2}=\sqrt{65}$

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$ .... (1)

where, (h,k) is center and r is radius.

The center of the circle is (0,0). So h=0 and k=0.

Substitute h=0, k=0 and $r=\sqrt{65}$ in equation (1).

$(x-0)^2+(y-0)^2=(\sqrt{65})^2$

$x^2+y^2=65$

Therefore the equation of circle is $x^2+y^2=65$ .

5 0

3 years ago

What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

jekas [21]

Answer:

$Negative$

Step-by-step explanation:

$We\ have\ to\ find\ sign\ of\ 3xy^3\\\\x>0\ and\ y0,y$

4 0

3 years ago

Read 2 more answers

Man I'm having so much trouble​

Man I'm having so much trouble