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murzikaleks [220]
4 years ago
14

The perimeter of a rectangular garden is 26 feet. The length is 7 feet longer than the width. What is the length of the garden?

Mathematics
1 answer:
MrMuchimi4 years ago
4 0
The answer is to this is 16
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Flying against the wind, a jet travels 2190 miles in 3 hours. Flying with the wind, the same jet travels 9520 miles in 8 hours.
dezoksy [38]

Answer:

Velocity of jet in still air is 970 miles per hour and velocity of wind is 210 miles per hour.

Step-by-step explanation:

Jet's velocity against wind is

3040/4 = 760 miles per hour and flying with wind it is

8260/7 = 1180 miles per hour.

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

As such its velocity against wind is x − y and with wind is x + y and therefore

x − y = 760 and x + y = 1180

Adding the two 2 x = 1940 and x = 970 and y = 1180 − 970 = 210

Hence velocity of jet in still air is 970 miles per hour and velocity of wind is

210 miles per hour.

Actual Answer:

https://socratic.org/questions/flying-against-the-wind-a-jet-travels-3040-miles-in-4-hours-flying-with-the-wind

7 0
3 years ago
Check the add-on inside please tell me the answer.
labwork [276]
Answer is A.
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3 0
3 years ago
Determine whether the statement is true or false.<br> 13 € {1, 2, 3, ..., 10}<br> True<br> False
const2013 [10]

Answer:

Determine whether the statement is true or false.

13 € {1, 2, 3, ..., 10}

True

8 0
3 years ago
NEED HELP IS DUE IN 5 MINUTES JUST TELL ME WHAT TO PUT IN
xxMikexx [17]

Answer:

12x^2-22x-14

Step-by-step explanation

Hope this helps, rate this, thanks and brainliest

7 0
3 years ago
Read 2 more answers
A dog searching for a bone walks
drek231 [11]

Answer:

Comics6366

05/20/2020

Mathematics

Middle School

answered

a dog searching for a bone walks 3.5 m southeast, then 8.2 m at an angle 30 degrees north of east. Find the magnitude of the dog's resultant vector

1

SEE ANSWER

Comics6366 is waiting for your help.

Add your answer and earn points.

OutsideSong

Answer:

Step 1: Firstly, we draw both of the axes.

Step 2: We then draw a vector of length 3.5 m (theoretical) along the (-x) axis.

Step 3: Next, we draw a vector of length 8.2 m from the endpoint towards to top, at an angle of 60° from that point (N.B: 90-30, since it is required to make a 30°∠ with the current vertical; eventually the triangle being formed will be 90° minus the 30°.) Most importantly, the 8.2 m vector should be drawn in such a way so that it is higher than the starting point of the 3.5 m vector. )

Step 4: Lastly, we draw a 15 m vector from the endpoint of the 8.2 m vector, running above the original vector, and to the left. This one should be drawn on the left side, and must be situated far enough.

∴ Triangle 1 () is of angles 30°, 60° and 90°;

On solving for the vertical side (the slope similar to the 3.5 vector), we get

(8.2/2) m = 4.1 m

Next, we solve for the opposite side via 4.1 × √3= 7.1 m

Moving on to Triangle 2 (),

top side = (15 - 7.1) m = 7.9 m

similarly, right side = (4.1 - 3.5) m = 0.6 m

∴ last side = resultant displacement:

⇒ + (0.6)² = 7.9 m

and, direction of displacement = arcTan(y/x)

= arcTan(0.6/7.9)

= 4.3° north of west

3 0
3 years ago
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